we conclude that the difference quotient for the function f(x), we get:
[-3*(2x + h) + 4]
<h3>
How to find the difference quotient for the function f(x)?</h3>
For any function f(x), we define the difference quotient as:
( f(x + h) - f(x))/h
In this case, we have:
f(x) = -3x^2 + 4x + 10
Then f(x) is a quadratic function.
Now we replace that in the difference quotient formula so we get:
[ -3(x + h)^2 + 4*(x + h) + 10 - (-3x^2 + 4x + 10)]/h
Now we can simplify that:
[ -3(x + h)^2 + 4*(x + h) + 3x^2 - 4x ]/h
[ -3(x + h)^2 + 4*h + 3x^2 ]/h
[ -3(x^2 + 2xh + h^2) + 4*h + 3x^2 ]/h
[ -3(2xh + h^2) + 4*h]/h = [-3*(2x + h) + 4]
So we conclude that the difference quotient for the function f(x), we get:
[-3*(2x + h) + 4]
If you want to learn more about difference quotients:
brainly.com/question/24922801
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