Question

the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/sec and L is the length ,in feet, of the animal's leg.To the nearest hundredth how many greater is the maximum walking speed of giraffe with a leg length of 6 feet than a hipppotamus with a leg length of 3 feet.

Answer 1

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Calculating Maximum speed

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
and L is the length of the animal's leg

Thus,

For a Giraffe with a leg length of 6 feet

S = √32×6

S = √192

S = 13.856 ft/sec

For a Hippopotamus with a leg length of 3 feet

S = √32×3

S = √96

S = 9.798 ft/sec

Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

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