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Triss [41]
1 year ago
12

Raíz cuadrada de 864

Mathematics
1 answer:
marshall27 [118]1 year ago
8 0

Raíz cuadrada de 864

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

The general equation of ellipse is given as, x2a2+y2b2=1 x 2 a 2 + y 2 b 2 = 1 , where, a is length of semi-major axis and b is length of semi-minor axis.

centro: (0,0)

focus : (0, -√28) , (0, √28)

eje conjugado = 2√3

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

de los focos podemos obtener que: √28

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b = √3

podemos utilizar la siguiente fórmula para obtener a:

si despejamos a en la ecuación obtenemos lo siguiente:

ahora podemos sustituir los valores:

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

si graficamos la hipérbola, queda como en el documento adjunto.

To learn more hipérbola

Visit : brainly.com/question/24223341

#SPJ9

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3 years ago
Marla bought 12 books at a garage sale. Some of them were hardback and the rest were paperback. She paid $0.50 for each paperbac
olga nikolaevna [1]

Answer: The number of books bought were 9 paperbacks and 3 hardbacks

Step-by-step explanation: We shall start by assigning letters to the unknown variables, hence let the hardback be called h, while the paperback shall be called p.

If Marla bought 12 books at the garage sale, that means she bought

h + p  = 12 ------(1)

Then she paid 0.5 dollars for paperback and 0.75 dollars for hardback and the total spent was 6.75 dollars for all of them, then we can express these as follows;

0.5p + 0.75h = 6.75 ------(2)

We now have a pair of simultaneous equations which are

h + p = 12 ------(1)

0.5p + 0.75h = 6.75 ------(2)

From equation (1), make h the subject of the equation,

h = 12- p

Substitute for h into equation (2)

0.5p + 0.75(12 - p) = 6.75

0.5p + 9 - 0.75p = 6.75

0.5p - 0.75p = 6.75 - 9

-0.25p = -2.25

Divide both sides of the equation by -0.25

p = 9

Now, substitute for p into equation (1)

h + p = 12

h + 9 = 12

Subtract 9 from both sides of the equation

h = 3

Therefore Marla bought 9 paperbacks and 3 hardbacks

6 0
3 years ago
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in order to find ab, you plug in the x into the expression.

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do the same for bc:

bc = x + 17
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and for ac, combine the two expressions and plug in the value for x.

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Step-by-step explanation:

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