All categories

3 years ago

Which of the following ordered pairs could be the y-intercept of a function?

Mathematics

1 answer:

Juliette [100K]3 years ago

7 0

Answer:

Step-by-step explanation:

The y intercept only occurs when x=0 so (0,0) is the only y intercept of those choices.

You might be interested in

What is the value of 12.5(- 2¾)

mote1985 [20]

The answer is -34.375

6 0

3 years ago

Read 2 more answers

Whoever answers this correctly gets brainlist!

Gnoma [55]

Answer:

5. 3/10

6. 7/12

7. 7/8

8. 4/3

Step-by-step explanation: Hope this helps!

7 0

3 years ago

Read 2 more answers

£70 is divided between Natasha, Richard & Stephen so that Natasha gets twice as much as Richard, and Richard gets three time

Korvikt [17]

The share of Natasha is £ 42

Solution:

£70 is divided between Natasha, Richard & Stephen

Total amount = 70

Let the share of natasha be "x"

Let the share of richard be "y"

Let the share of stephen be "z"

Natasha gets twice as much as Richard

x = 2y ------ eqn 1

Richard gets three times as much as Stephen

y = 3z

$z = \frac{y}{3}$ ----- eqn 2

Total amount = 70

share of natasha + share of richard + share of stephen = 70

x + y + z = 70

Substitute eqn 1 and eqn 2

$2y + y + \frac{y}{3} = 70\\\\\frac{6y+3y+y}{3} = 70\\\\10y = 210\\\\y = 21$

Substitute y = 21 in eqn 1

x = 2y = 2(21) = 42

x = 42

Thus natasha gets £ 42

6 0

3 years ago

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$

Where $_nC_x$ is the number of different combinations of x success in n trials.

$_nC_x=\frac{x!}{n!(n-x)!}$

Hence,

$P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}$

$_9C_4=\frac{4!}{9!(9-4)!}=126$

$P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125$

b) Probability that at most 3 flights are on time

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

$P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(0.5)^9=0.00195313$ . . . (the probability that all are not on time)

$P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625$

$P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125$

$P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625$

$P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\ P(X\leq 3) \approx 0.0293$

c) Probability that at least 8 flights are on time 

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

$P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586$

6 0

4 years ago

Jack thinks the ordered pairs below could be solutions to a linear equation,but Sally disagrees. Who is correct? Justify your an

I am Lyosha [343]

who is jack is that your crush?

6 0

3 years ago