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DiKsa [7]
3 years ago
10

How do I find the answer to the second question?

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0
The sentence does not make sense because a test can only be 100% not 200

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Please help me need ASAP
solniwko [45]

Answer:

3)Quadratic

Step-by-step explanation:

Brainliest?

4 0
2 years ago
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
yKpoI14uk [10]

Answer:

<h3>Step-by-step explanation: for #2, look at 6 3/4 and make it into a decimal. Do the same to 7 1/2. Compare them both to see which one is shorter by subtracting 6 3/4 from 7 1/2 and when you get your answer for that, make that into a fraction. Predict that 6 3/4 is shorter because of how much less it is compared to 7 1/2.  (I hope I helped you in some way. Good luck!)</h3>
7 0
3 years ago
If you rolled two dice, what is the probability
Softa [21]

Answer:

2/36 or 1/18 simplified

Step-by-step explanation:

you have all the combinations listed which is good.

probability = number of successful events / number of total events

  • look for the sums that are 11 and count them (there are 2 - 5,6 and 6,5).
  • total the number of all events (36)
  • so you then get the 2/36

there are

5 0
2 years ago
How do you do this question?
Alex Ar [27]

Step-by-step explanation:

(a) dP/dt = kP (1 − P/L)

L is the carrying capacity (20 billion = 20,000 million).

Since P₀ is small compared to L, we can approximate the initial rate as:

(dP/dt)₀ ≈ kP₀

Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.

20 = k (6,100)

k = 1/305

dP/dt = 1/305 P (1 − (P/20,000))

(b) P(t) = 20,000 / (1 + Ce^(-t/305))

6,100 = 20,000 / (1 + C)

C = 2.279

P(t) = 20,000 / (1 + 2.279e^(-t/305))

P(10) = 20,000 / (1 + 2.279e^(-10/305))

P(10) = 6240 million

P(10) = 6.24 billion

This is less than the actual population of 6.9 billion.

(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))

P(100) = 7570 million = 7.57 billion

P(600) = 20,000 / (1 + 2.279e^(-600/305))

P(600) = 15170 million = 15.17 billion

7 0
2 years ago
The processing speed of a certain computer is 10¹¹ instructions per second. Another computer has a processing speed that is 10³
Mashcka [7]
“Times as fast” means you need to multiply the original speed (10^11) by how many times faster the faster processor works:

10^11 instructions/second • 10^3 faster = 10^14 instructions/second

The key is “___ times as fast”.
7 0
2 years ago
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