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ira [324]
3 years ago
5

A grocer mixed 3 types of white, green and black tea in 3:5:7 ratio, respectively. How many kilograms of each are needed to make

6 kg of that mixture?
Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

There are 6/5 white, 2 green, and 14/5 black

Step-by-step explanation:

Think of it like this.

First we add up everything.

3x+5x+7x = 6kg

15x=6

We find x and plug it in to the equation.

x=2/5

3*2/5=6/5  (6/5 is white)

5*2/5=2      (2 is green)

7*2/5=14/5   (14/5 is black)

There are 6/5 white, 2 green, and 14/5 black

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Theresa has to pay back 5000 in student loans. She can afford to pay 150 per month. Write a linear function that describes this
LenKa [72]

Answer:

p = 5000 - 150 * m

Step-by-step explanation:

We need a function that tells us the total value to pay with respect to the student loan, Theresa has a monthly fee so that each time passes she would have to pay less.

Therefore, the total of paying over time would be the initial value of the loan minus the fixed value that must be paid for the amount of time, in this case months, as follows:

p = 5000 - 150 * m

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3 years ago
MARKING BRAINLEST!!!!!!
Rus_ich [418]

Answer:

D. 8.4* 10^8

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Use the disk method or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs
JulsSmile [24]

Answer:

1) V = 12 π  ㏑ 3

2) \mathbf{V = \dfrac{328 \pi}{9}}

Step-by-step explanation:

Given that:

the graphs of the equations about each given line is:

y = \dfrac{6}{x^2}, y =0 , x=1 , x=3

Using Shell method to determine the required volume,

where;

shell radius = x;   &

height of the shell = \dfrac{6}{x^2}

∴

Volume V = \int ^b_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = \int ^3_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = 12 \pi \int ^3_{x-1} \dfrac{1}{x} \ dx

V = 12 \pi ( In \ x ) ^3_{x-1}

V = 12 π ( ㏑ 3 - ㏑ 1)

V = 12 π ( ㏑ 3 - 0)

V = 12 π  ㏑ 3

2) Find the line y=6

Using the disk method here;

where,

Inner radius r(x) = 6 - \dfrac{6}{x^2}

outer radius R(x) = 6

Thus, the volume of the solid is as follows:

V = \int ^3_{x-1} \begin {bmatrix}  \pi (6)^2 - \pi ( 6 - \dfrac{6}{x^2})^2  \end {bmatrix} \ dx

V  =  \pi (6)^2 \int ^3_{x-1} \begin {bmatrix}  1 - \pi ( 1 - \dfrac{1}{x^2})^2  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  1 -  ( 1 + \dfrac{1}{x^4}- \dfrac{2}{x^2})  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  - \dfrac{1}{x^4}+ \dfrac{2}{x^2} \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  {-x^{-4}}+ 2x^{-2} \end {bmatrix} \ dx

Recall that:

\int x^n dx = \dfrac{x^n +1}{n+1}

Then:

V = 36 \pi ( -\dfrac{x^{-3}}{-3}+ \dfrac{2x^{-1}}{-1})^3_{x-1}

V = 36 \pi ( \dfrac{1}{3x^3}- \dfrac{2}{x})^3_{x-1}

V = 36 \pi \begin {bmatrix} ( \dfrac{1}{3(3)^3}- \dfrac{2}{3}) - ( \dfrac{1}{3(1)^3}- \dfrac{2}{1})    \end {bmatrix}

V = 36 \pi (\dfrac{82}{81})

\mathbf{V = \dfrac{328 \pi}{9}}

The graph of equation for 1 and 2 is also attached in the file below.

5 0
4 years ago
Which number has the same value as 20 tens
Leviafan [203]
200.

Twenty groups of ten = 20x10
20x10 = 200
3 0
3 years ago
Read 2 more answers
The diagram shows a right-angled triangle.
o-na [289]
You have the opposite and the hypotenuse given. So you use the sine ratio

Sin x = 6/9

x= sin inverse of 6/9 = 41.8 degrees
5 0
3 years ago
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