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alukav5142 [94]
1 year ago
5

six construction workers that work at the same rate can build a house in $1.5$ days. how many days does it take $15$ constructio

n workers, working at the same rate, to finish building a house? express your answer as a fraction in lowest terms.
Mathematics
1 answer:
navik [9.2K]1 year ago
6 0

The 15 workers, working at the same rate, will finish the house in 0.8 days.

<h3>How much time the 15 workers need to finish the house?</h3>

We assume that all the workers work at the same rate R.

The 8 workers can finish one house in 1.5 days, then:

(8*R)*1.5 days = 1 house.

Solving that for R we get:

R = (1/(1.5*8)) houses/day = 0.083 houses/day.

Now, if now there are 15 workers, then the rate for the 15 working together is:

15*R = 15*0.083 houses/day. = 1.25 houses/day.

They will construct a house in a time T such that:

(1.25 houses/day)*T = 1 house.

T = (1 house)/(1.25 houses/day) = 0.8 days.

The 15 workers, working at the same rate, will finish the house in 0.8 days.

If you want to learn more about working rates:

brainly.com/question/14305692

#SPJ1

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Question:A water tank is shaped like the cone shown here. How much water can the tank​ hold? Use 3.14 for . If water is drained from the tank to fill smaller tanks that each hold 200 m³ of​ water, how many smaller tanks can it fill

Answer:

Amount of water = 871.87 in³

Number of tanks = 4 tanks

Step-by-step explanation:

Applying,

V = 1/3πr²h........... Equation 1.

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From the diagram attached,

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Substitute these values into equation 1

V = 1/3(17)(7²)(3.14)

V = 871.87 m³.

Hence the amount of water the tank can hold is 871.87 m³

If the water is drained to a tank of 200 m³,

The number of tanks it can fill is = 871.87/200 = 4 tanks.

3 0
3 years ago
What is the solution to this system of equations? {5x+4y=22 3x+4y=10
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Multiply 2nd equqation by -1 and add to first

5x+4y=22
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2x+0y=12

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3 years ago
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Find the cos A and tan B to four decimal places. URGENT
Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

<u>Pythagoras theorem</u>

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hypotenuse^{2} = 8^{2} + 5^{2}

hypotenuse^{2} = 64 + 25

hypotenuse = \sqrt{89}

hypotenuse = 9.4

a) Cos A

<u>Data:</u>

Adjacent = 8

Hypotenuse = 9.4

<u>Formula:</u>

Cos (Angle) = \frac{adjacent}{hypotenuse}

Cos A =  \frac{8}{9.4}

Cos A = 0.8511

A = cos^{-1} (0.8511)

A = 31.7°

b) Tan B

<u>Data: </u>

Opposite = 8

Adjacent = 5

<u>Formula:</u>

Tan (Angle) = \frac{opposite}{adjacent}

Tan B = \frac{8}{5}

Tan B = 1.6

B =  cos^{-1} (1.6)

B = 58°

Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

Learn more about cos at

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

please give me brainlest and follow me

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