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neonofarm [45]
3 years ago
6

A national publication showed the following distribution of favorite class subjects for high school students.

Mathematics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

1 and 111 only

Step-by-step explanation:

The goodness of fit test is used to examine if there is significant evidence to say thatvthe observed and expected freqencies are from the desired distribution.

Condituis required for performing a goodness of fit test on a data include :

Randomness, sampled Data must have been chosen at random in other to be representative, here, randomness isn't exhibited as Pasquale used more of convenient sampling questioning the first 40 students.

Also, the expected value of the number of sample observation in each level of the variable should be atleast 5.

This is also violated, as the expected values for some of the levels are less than 5

Hence, conditions 1 and 111 are not met

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R=8cos3 theta graph plz graph it for me
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3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
I answered it but I just need someone to answer just to make sure mine are right
Artemon [7]
<h2>The missing measures of the angles are:</h2>

m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

<u>Given</u>:

m\angle Z = 138^{\circ}

<em><u>Note the following:</u></em>

  • An equilateral triangle has all its three angles equal to each other. Each angle = 60^{\circ}.
  • This implies that, since \triangle WXY is equilateral, therefore, m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}

  • Base angles of an isosceles triangle are congruent to each other.
  • This implies that, since \triangle WZY is isosceles, therefore, m\angle 3 = \angle 5

Applying the above stated, let's find the measure of each angle:

  • Find m\angle 1

m\angle 1 = 60^{\circ} (an angle in an equilateral triangle equals 60 degrees)

  • Find m\angle 2

m\angle 2 = 60 - m \angle 3

m\angle 2 = 60 -\frac{1}{2}(180 - 138) (Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)

m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}

  • Find m\angle 3 and m\angle 5 (base angles of isosceles triangle WZY)

m\angle 3 =  \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)

m\angle 3 =  \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}

m\angle3 = m\angle 5 (base angles of isosceles triangle are congruent)

Therefore,

m\angle5 = 21^{\circ}

  • Find m\angle 4

m\angle 4 = 60 - m\angle 5

Substitute

m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}

The missing measures of the angles are:

m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

Learn more here:

brainly.com/question/2944195

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A Converse Statement is when you turn the statement into a double negative?
Misha Larkins [42]

Answer:

False

Step-by-step explanation:

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2 years ago
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