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Musya8 [376]
2 years ago
4

Answer for i^372 And i^527 with explanation please

Mathematics
1 answer:
Gnoma [55]2 years ago
5 0
<h2>Answer </h2>

i {}^{372}  = 1 \\ i {}^{527 }  =  - i

Step-by-step explanation:

Greetings !

<u>Note that:-</u>

<u>i {}^{2n}  = 1.\: if \: n \: is \: even \\  \:  \:  \:  \:   \:  \:  \:  = - 1. \: if \: n \: is \: odd</u>

And also

i {}^{2n + 1}  = i. \: if \: n \: is \: even \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =   - i.\: if \: n \: is \: dd

Thus, remembering these general formula plug in values in the place of n and solve.

Therefore,

i {}^{2(186)}  = i {}^{372}  = 1

where n is even thus its 1 from the above explanation

i {}^{2(263) + 1}  = i {}^{527}  =  - i

following the same procedure the values exceeds to be -i.

Hope it helps !!!

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