All categories

2 years ago

Being cleaner and longer-burning compared with

Mathematics

1 answer:

givi [52]2 years ago

4 0

(C) "Cleaner and longer-burning than"

The highlighted paragraph is grammatically incorrect and makes little sense in the context because the words "being" and "compared" conflict with the remainder of the sentence's tense structure.

Only C fixes this mistake without introducing a new one (s). The past, present, and future tenses of a verb are available. Things from the past are things that have already occurred (earlier in the day, yesterday, last week, three years ago).

The present tense is used to talk about things that are ongoing or that are currently happening now. Things that are yet to occur are described in the future tense.

Here's another question with an answer similar to this about tenses:

brainly.com/question/11222622

#SPJ4

You might be interested in

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago

Adding proper fractions .. 10/12+6/12=need help

mixas84 [53]

Adding fractions is easy when you get the rules...
10/12 + 6/12...
add the numerator which is the top, and keep the denominator which is the bottom.
10/12 +6/12 = 16/12
change that into a mixed number
16/12 = 1 4/12 which is simplified to 1 1/3
hope this helps

3 0

3 years ago

Read 2 more answers

when johns age is doubled, the number is 5 more than kaylas age. if john is x years old, what is kayalas age?

Sunny_sXe [5.5K]

Answer:

Ang mga Babae sa Relihiyon at Pilosopiya sa Asya. Limang Ugnayan. emperador-mamamayan. ama-anak na lalaki.

3 0

2 years ago

I need to find the slope-intercept form of the equation of the line through (-5,-2) and (-3,4)

Vlad [161]

Answer: