The domain of the function f(x)=x+10 is (-∞, ∞) and for the function g(x)=x² is (-∞, ∞).
<h3>What is meant by domain?</h3>
If a formula specifies a real function f, it may not be defined for some values of the variable. The natural domain or domain of definition of f is the set of real numbers on which the formula can be evaluated to a real number in this case. A partial function is often referred to just as a function, and its natural domain is referred to simply as its domain.
Given, f(x) = x + 10
g(x)=x²
The domain for the function f(x)=x + 10
So, the domain of f(x)=x+10 is (-∞, ∞)
The domain for the function g(x)=x²
The expression's domain is only real numbers, with the exception of places where it is undefined. Because there is no real number in this scenario, the expression is undefined.
So, the domain of the function g(x)=x² is (-∞, ∞)
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Answer: x=21
Step-by-step explanation: 100+x-4+3x=180
4x=84
x=21
Answer:
-27
Step-by-step explanation:
order of operations 2÷2 = 1 +53 =54
3x1 = 3 -5 = -2
54÷-2 = -27
Answer:
B
C
A
Step-by-step explanation:
Find the value of x in each equation then compare the solutions from the least to the greatest
<u>In A</u>
5( x-6)+3x=3/4(2x-8) ------------Open brackets
5x-30+3x=3/2x-6
5x+3x-30=3/2x-6
8x-3/2x=-6+30---------------collect like terms
16x-3x=48
13x=48-----------------dived both sides by 13
x=48/13 = 3.7
<u>In B</u>
2.7(5.1x+4.9)=3.2+28.9-------------open bracket
13.77x+13.23=32.1
13.77x=32.1-13.23---------------collect like terms
13.77x=18.87
x=18.87/13.77----------------------divide both sides by 13.77
x=1.37
<u>In C</u>
5(11x-18)=3(2x+7)--------------------open brackets
55x-90=6x+21
55x-6x=21+90-----------------------collect like terms
49x=111----------------------------------divide both sides by 49 to get x
x=111/49 = 2.27
From the solutions, the least value of x is in B, then C ,and finally A
Answer: x=1+1/3
Step-by-step explanation: -(3x-12)=9x-4
We move all terms to the left:
-(3x-12)-(9x-4)=0
We get rid of parentheses
-3x-9x+12+4=0
We add all the numbers together, and all the variables
-12x+16=0
We move all terms containing x to the left, all other terms to the right
-12x=-16
x=-16/-12
x=1+1/3