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makkiz [27]
1 year ago
15

Can someone help me, i cant find the anwser

Mathematics
1 answer:
Aloiza [94]1 year ago
5 0

The range of the given function is represented by  {-6,-4,2}.

<h3>Domain and Range</h3>

The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.

While the domain is related to the values ​​of x, the range is related to the possible values ​​of y that the function can have.

Here, you need to replace the given domain values in the equation: f(x)=x-4. The question gives that the domain is represented by: -2 ,0 ,2 .

Thus,

For x=-2, you have:

f(x)= x-4

f(x)= -2-4

f(x)= -6

For x=0, you have:

f(x)= 0-4

f(x)= 0-4

f(x)= -4

For x=2, you have:

f(x)= x-4

f(x)= 2-4

f(x)= -2

Therefore, the range of the given function is {-6,-4,2}

Learn more about the range here:

brainly.com/question/10197594

#SPJ1

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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

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