Answer:
The correct answer is ![\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D)
Step-by-step explanation:
A fair coin is tossed three times in a succession the sample space is shown where h represents a head and t represents a tail.
Let the experiment A denote that we get exactly one tail in three successive toss of a coin.
Sample space = { hhh, hht, hth, thh, tth, tht, htt, ttt} = 8
Favorable sample = { hht, hth, thh } = 3
Probability of the A =
=
= 0.375.
Thus the probability of getting exactly one tail in three successive toss of a fair coin is given by 0.375
First, we can start by expanding (a+b)²
a²+2ab+b²
We can then use the commutative property to separate this into:
a²+b² + 2ab
Since we are given the values for <span>a²+b² and ab, we can</span> plug in these values into the equation:
16 + (2)(8)
16+16
32
Therefore, the value of (a+b)² is 32
The answer could be .317
(not could be as in I don't know but could be as is it's an option)