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Over [174]
3 years ago
12

Amber got a raise. Her hourly wage increased from $8 to $10 an hour. How much did amber's hourly wage increase.

Mathematics
2 answers:
vovangra [49]3 years ago
6 0

Answer:

Her wage increased by $2 an hour

Step-by-step explanation:

shusha [124]3 years ago
6 0

Answer:

2 dollars.

Step-by-step explanation:

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625,000,000

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25000 x 25000

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A rectangular garden has vertices at (4, 3), (6, 3), (6, 9), and (4, 9). Plot each vertex of the garden.
kati45 [8]

Answer:

Step-by-step explanation:

A rectangular garden has vertices at

(x = 4, y = 3), (x = 6, y = 3), (x = 6, y = 9), and (x = 4, y = 9).

To plot each vertex of the garden find on the graph the x and y coordinate of the point and mark the point.

3 0
2 years ago
The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in
Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 64 inches

           \sigma = standard deviation = 4 inches

           n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{63-64}{\frac{4}{\sqrt{4} } } ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

                                                        = 1 - 0.69146 = 0.30854

Hence, it is 30.85%  likely that average height would be shorter than 63 inches.

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4 years ago
What is the integral of 1/(y²-1)
ANTONII [103]
Hello here is a solution : 

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4 years ago
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