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Nikitich [7]
2 years ago
6

On a coordinate plane, 2 parallelograms are shown. Parallelogram 1 has points (0, 2), (2, 6), (6, 4), and (4, 0). Parallelogram

2 has points (2, 0), (4, negative 6), (2, negative 8), and (0, negative 2). How do the areas of the parallelograms compare? The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2. The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2. The area of parallelogram 1 is equal to the area of parallelogram 2. The area of parallelogram 1 is 2 square units less than the area of parallelogram 2.
Mathematics
1 answer:
Murrr4er [49]2 years ago
8 0

The areas of the parallelograms compare by option : A. The area of parallelograms 1 is 4 square units greater than the area of parallelogram 2.

<h3>What is the parallelograms  about?</h3>

Note that the part that is filled by a flat form or the surface of an item is called the  area.

Note that:

A₁ =  the area of parallelogram 1

A₁ = the area of parallelogram 2

l₁ = the distance between the points that is (2,6),(0,2)

l₂ = the distance between the points that is (4,0)(0,2)

b₁ = the distance between the points  that is (2,0),(0,-2)

b₂ = the distance between the points that is (2,6),(4,-6)

So

A₁ =  l₁ × b₁

=4.47 ×4.47

19.89 sq. unit

A₂= l₂×b₂

2.82 × 6.342

17.88 sq. unit

A₁-A₂ = 19.89 sq. unit - 17.88  sq. unit'

         =  2.01

Therefore, The areas of the parallelograms compare by option : A. The area of parallelograms 1 is 4 square units greater than the area of parallelogram 2.

Learn more about parallelograms from

brainly.com/question/23774966

#SPJ1

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Step-by-step explanation:

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<u>Part B:</u>

The algebric expression for: "StartFraction one-half EndFraction left-parenthesis n minus 4 right-parenthesis minus 3 equals 3 minus left-parenthesis 2 n plus 3 right-parenthesis" will be ⇒ \frac{1}{2}(n-4)-3=3-(2n+3)

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