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3 years ago

If m∠acd = 100 and m∠b= 60 find m∠a

Mathematics

1 answer:

krek1111 [17]3 years ago

7 0

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5x-2y=-6 3x-4y = -26

snow_tiger [21]

For this case we must solve the following system of equations:

$5x-2y = -6\\3x-4y = -26$

We multiply the first equation by -2:

$-10x + 4y = 12$

We add the new equation with the second one:

$-10x + 3x + 4y-4y = 12-26$

We have different signs subtracted and the sign of the major is placed:

$-7x = -14\\x = \frac {-14} {- 7}\\x = 2$

Now we find the value of the variable "y":

$3x-4y = -26\\3 (2) -4y = -26\\6-4y = -26\\-4y = -26-6\\-4y = -32\\y = \frac {-32} {- 4}\\y = 8$

Thus, the solution of the system is given by:

$(x, y) :( 2,8)$

Answer:

$(x, y) :( 2,8)$

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4 years ago

Help im sister needs help and i can't help her im doing my school work !

padilas [110]

Answer is 73 because blah blah blah blah

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3 years ago

Stacy rowed across the lake with her friend Rainey (in the same boat) at a rate of 3 mph. Rainey then rowed back at a rate of 2

Debora [2.8K]

Multiply then divide

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3 years ago

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Find the magnitude and direction in degrees of the vector v=6i+2 seq31

masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the vector

v = 6i + 2√3j

The Magnitude of a vector:

$\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}$

$=\sqrt{6^2+\left(2\sqrt{3}\right)^2}$

$=\sqrt{36+12}$

$=\sqrt{48}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

$=\sqrt{3}\sqrt{2^4}$

$=4\sqrt{3}$

The Direction of a vector:

tan Ф = y/x

y=2√3

x = 6

tan Ф = y/x

= 2√3 / 6

= √3 / 3

$\theta \:=tan\:^{-1}\left(\frac{\sqrt{3}}{3}\right)$

$\:\theta \:=\frac{\pi \:}{6}=30^{\circ \:}$

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3 years ago

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AysviL [449]

The answer is for x is x = 60

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