6c^2 - c + 1 + 4c - 2c^2 - 8c
= 4c^2 - 5c + 1
= (4c - 1)(c - 1)
It’s c because if you look at it shows that it could do straight line
Knowing that there are two logs on both sides of the brackets, they cancel out.
This leaves:
4y-1=2y+7 (solve for y)
4y-2y=7-1
2y=6
y=3
Hope this helped :)
<span>Together with triangles, circles comprise most of the GMAT Geometry problems.
A circle is the set of all points on a plane at the same distance from a single point ("the center").
The boundary line of a circle is called the circumference.</span>
According to the solving the perimeter of the given triangle is:
= -x³ + 13x² + 11x + 20
<h3>Describe the triangle:</h3>
Three edges and three vertices make up a triangle, which is a polygon. It is among the fundamental shapes in geometry. Triangle ABC refers to a triangle with the vertices A, B, and C. In Euclidean geometry, any three points that are not collinear determine a singular triangle and a singular plane at the same time.
<h3>What is the formula for the triangle's perimeter?</h3>
Simply summing the lengths of all the sides of a triangle yields its perimeter. A + B + C is the basic formula to determine the perimeter of a triangle with sides "a," "b," and "c."
<h3>According to the given data:</h3>
A = 9x+10x²-x³
B = -x² + 9x + 12
C = 4x²-7x+8
We know that the perimeter of the triangle is sum of all side of the triangle:
A+B+C
= (9x+10x²-x³) + (-x² + 9x + 12)+(4x²-7x+8)
= -x³ + 13x² + 11x + 20
To know more about Triangle visit:
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