Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =2 y' = - 1
calculate a :
let : y = ax+b .....(D)
....<span>3y-x=7</span>....(D') or y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line : y-y' =a(x-x')
y+1 =(-3) (x-2)
Answer:
Distance of Tunnel is 500 meters + Train travel rate is 20 meters per second = 25 seconds to pass through the tunnel only therefore the outstanding balance of 35 seconds x 20 meters per second =600 meters Train
Step-by-step explanation:
Total of length of train 600 meters and tunnel (500 meters) is 1,200 meters +30 seconds = TR of 20 meters per second
Answer:it is linear because every time x increases 1, y increases by 2.
Step-by-step explanation:it is a linear relationship and it is changing at a constant rate
I am just guessing but you might try A
34/50= .68 or 68%
hope it helps