<span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 to give result as 9x^2 -2x - 5
</span>3x^2 + 4x + 8 + 2x^2 - 6x + 3
= 5x^2 - 2x + 11
so
9x^2 -2x - 5 - (5x^2 - 2x + 11)
= 9x^2 -2x - 5 - 5x^2 + 2x - 11
= 4x^2 -16
answer
expression (4x^2 -16) must be added to the sum of (3x^2 + 4x + 8) and (2x^2 - 6x + 3) to give the result as (9x^2 - 2x - 5)
Answer:
0
Step-by-step explanation:
Sq32/8 = sq4
It would be c. 2
Answer:
4 parts 3
Step-by-step explanation:
Answer:
The 26th term of an arithmetic sequence is:

Hence, option A is true.
Step-by-step explanation:
Given
An arithmetic sequence has a constant difference 'd' and is defined by

substituting a₁ = -33 and d = 4 in the nth term of the sequence



Thus, the nth term of the sequence is:

now substituting n = 26 in the nth term to determine the 26th term of the sequence




Therefore, the 26th term of an arithmetic sequence is:

Hence, option A is true.