Well first you have to add common like terms in this case 2r and -6r to get -4r now your equation is -4r+8=40, now subtract 8 from both sides to leave r by itself and get -4r=32, now divide both sides by -4 to get r=-8
Hope this helps
Answer:
b. complementary
Step-by-step explanation:
-Complementary angles are angles that add up to 90°.
-These are usually the two acute angles in the right triangle.
#To verify, lets take the two angles 30° and 60°:

#We can reverse as:

Hence, two angles are said to be complimentary if they sum up to 90°.
Answer:
Aaron must obtain a 96 or higher to achieve the desired score to earn an A in the class.
Step-by-step explanation:
Given that the average of Aaron's three test scores must be at least 93 to earn an A in the class, and Aaron scored 89 on the first test and 94 on the second test, to determine what scores can Aaron get on his third test to guarantee an A in the class, knowing that the highest possible score is 100, the following inequality must be written:
93 x 3 = 279
89 + 94 + S = 279
S = 279 - 89 - 94
S = 96
Thus, at a minimum, Aaron must obtain a 96 to achieve the desired score to earn an A in the class.
2.3= 2.03 so there for it is equal
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.