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Nina [5.8K]
1 year ago
14

Jason considered two similar televisions at a local electronics store. the cheaper version was 12 inches by 24 inches. the more

expensive version was \large \frac{8}{3} the size of the cheaper one. what are the dimensions of the expensive television? a 4.5 inches by 9 inches b 28 inches by 56 inches c 7.5 inches by 15 inches d 32 inches by 64 inches
Mathematics
1 answer:
Vaselesa [24]1 year ago
6 0

The dimensions of expensive television is 32 inches through 64 inches.

This trouble may be solved if we understand the idea of fraction and a way to calculate the part of a fragment.

right here it is for the reason that the inexpensive tv is 12 inches by means of 24 inches.

Also it is given that the expensive television is \frac{8}{3} of the cheaper one.

Now taking the length into consideration the length of the television is

  =\frac{8}{3}*12

  = 32 inches

Now taking the width into consideration the width of the television is

 =\frac{8}{3}*24

 = 64 inches

So, the dimension of the expensive television is 32 inches by 64 inches.

To learn more about fractions visit the link:

brainly.com/question/10354322

#SPJ4

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A random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph. From past information, it is kn
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Answer:

95 percent confidence interval for μ is determined by

(60.688 ,  69.312)

a) be the same

Step-by-step explanation:

<u>Step (i)</u>:-

Given data a random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph.

The sample size is n= 121

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

<u>Step (ii) :</u>-

Given  The 95 percent confidence interval for μ is determined as

(61.08, 68.92)

we are to reduce the sample size to 100 (other factors remain unchanged) so

given The sample size is n= 100

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

<u>Step (iii)</u>:-

95 percent confidence interval for μ is determined by

(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96 \frac{S.D}{\sqrt{n} } )

(65 - 1.96\frac{22}{\sqrt{100} } , 65 + 1.96 \frac{22}{\sqrt{100} } )

(65 - 4.312 ,65 +4.312)

(60.688 ,  69.312) ≅(61 ,69)

This is similar to (61.08, 68.92) ≅(61 ,69)

<u>Conclusion</u>:-

it become same as (61.08, 68.92)

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When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x).
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