Question

Jason considered two similar televisions at a local electronics store. the cheaper version was 12 inches by 24 inches. the more expensive version was \large \frac{8}{3} the size of the cheaper one. what are the dimensions of the expensive television? a 4.5 inches by 9 inches b 28 inches by 56 inches c 7.5 inches by 15 inches d 32 inches by 64 inches

Answer 1

The dimensions of expensive television is 32 inches through 64 inches.

This trouble may be solved if we understand the idea of fraction and a way to calculate the part of a fragment.

right here it is for the reason that the inexpensive tv is 12 inches by means of 24 inches.

Also it is given that the expensive television is $\frac{8}{3}$ of the cheaper one.

Now taking the length into consideration the length of the television is

  =$\frac{8}{3}*12$

  = 32 inches

Now taking the width into consideration the width of the television is

 =$\frac{8}{3}*24$

 = 64 inches

So, the dimension of the expensive television is 32 inches by 64 inches.

To learn more about fractions visit the link:

brainly.com/question/10354322

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