Jason considered two similar televisions at a local electronics store. the cheaper version was 12 inches by 24 inches. the more
1 answer:
The dimensions of expensive television is 32 inches through 64 inches.
This trouble may be solved if we understand the idea of fraction and a way to calculate the part of a fragment.
right here it is for the reason that the inexpensive tv is 12 inches by means of 24 inches.
Also it is given that the expensive television is of the cheaper one.
Now taking the length into consideration the length of the television is
=
= 32 inches
Now taking the width into consideration the width of the television is
=
= 64 inches
So, the dimension of the expensive television is 32 inches by 64 inches.
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So the midpoint of your segment is
Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points. Ditto for the y-coordinate of the midpoint; just average the y's.