All categories

3 years ago

7000 divided by ten squared

Mathematics

2 answers:

Hoochie [10]3 years ago

8 0

Answer:

70:) i think that’s the right answer.

Step-by-step explanation:

Nitella [24]3 years ago

4 0

7000/10=700.
Answer 700

You might be interested in

Debra travels a distance of 2 miles in 1 minute how much distance can she cover in 25 minutes

Marta_Voda [28]

Debra will travel 50 miles in 25 minutes

Step-by-step explanation:

Given

distance = 2 miles

Time = 1 minute

Other time = 25 minutes

We can use the proportions to find the number of miles debra will travel in 25 minutes

So,

$Distance:Time::Distance:Time\\2:1::Distance:25\\\frac{2}{1} = \frac{Distance}{25}\\Distance = 25 *2\\= 50\ miles$

Hence,

Debra will travel 50 miles in 25 minutes

Keywords: Proportion, rate

Learn more about proportion at:

#LearnwithBrainly

8 0

3 years ago

What is the coefficient of 43k?

OLEGan [10]

43.
The coefficient of something is the numerical value in that term. For example, if we have 4x. The coefficient is 4.

4 0

3 years ago

Read 2 more answers

Find radius of the sphere from the following volume

nordsb [41]

Can you send a picture by chance?

3 0

2 years ago

Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive

VikaD [51]

Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

$\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}$

recall that

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}$

therefore, let's just plug that on the remaining ones,

$\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}$

now, let's rationalize the denominator on tangent and secant,

$\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}$

3 0

3 years ago

Who is your fave celebrity

andrew-mc [135]

Answer:

arianna grande

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers