Question

How many cycles of oscillation does the radiation from a cesium-133 atom complete during one mosquito wing beat?.

Answer 1

The frequency of radiation from a Cesium-133 atom is 9,192,631,770 cycle/s

= $9.192631770$×$10^{9}$ cycles/s

The number of cycles of radiation in one second is $9.192631770$×$10^{9}$

The number of cycles during 1 mosquito wing beat,

i.e., the number of cycles in $\frac{1}{605} s$

= $(9.192631770$×$10^{9})$$(\frac{1}{605} )$

= $1.519$×$10^{7} cycles/beat$

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