After folding the paper 6 times, the number of boxes created will be 64.
We are given that:
Maria folded a piece of paper in half 6 times which can be analyzed as:
When she will fold it 1 time, the number of box created will be = 2.
Then, when she will again fold it 2nd time, the number of boxes created will be = 4
Then, in the 3rd time, the number of boxes created will be = 8.
So, we get the sequence as:
2, 4, 8 ...
This is a geometric sequence.
So, we get the 6th term as:
aₙ = a rⁿ⁻¹
Here a = 2, r = 2 and n = 6
Substituting the values, we get that:
a₆ = (2) (2)⁶⁻¹
a₆ = (2) (2)⁵
a₆ = 2 × 32
a₆ = 64
Therefore, we get that, after folding the paper 6 times, the number of boxes created will be 64.
Learn more about geometric progression here:
brainly.com/question/24643676
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