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Firdavs [7]
3 years ago
5

1 through 10....?....​

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
5 0

11

Brainliest ????? :)

Alex73 [517]3 years ago
3 0

Answer:

oh well you are very beautiful so it's 9/10

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EXREAMLY URGENT!! WILL FOREVER THANK YOU!!!! PLS JUST TAKE A LOOK!!!!! 1. What is the ratio of the sides of triangle XYZ?
sdas [7]

Answer:

Dear Laura Ramirez

Answer to your query is provided below

The ratio of triangle XYZ is 1:√3 :2.

Step-by-step explanation:

A 30-60-90 right triangle (literally pronounced "thirty sixty ninety") is a special type of right triangle where the three angles measure 30 degrees, 60 degrees, and 90 degrees. The triangle is significant because the sides exist in an easy-to-remember ratio: 1:√3 :2.

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3 years ago
I WILL GIVE BRIWNLIEST AND THANKS AND MORE POINTS TO CORRECT PERSON
AlekseyPX

Step-by-step explanation:

hi im not sure it's right it was kinda confusing

8 0
3 years ago
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Plz answer correctly will give 30 points.
TEA [102]

Answer:

20

Step-by-step explanation:

trust me.

6 0
3 years ago
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Oint C is on line segment BD‾\overline{BD} BD . Given BD=5x,BD=5x, BD=5x, BC=4x,BC=4x, BC=4x, and CD=4,CD=4, CD=4, determine the
Gennadij [26K]

Answer:

Therefore the required value of \overline{BD} is 20 units.

Step-by-step explanation:

Line Segment: Line segment is a portion of a line whose has two end points.

Given that point C is on the line segment \overline{BD}.

\overline{BD} = 5x , \overline{BC} = 4x and \overline{CD} = 4

C is the point of the line segment of \overline{BD}.

So we can write

\overline {BD}= \overline{BC}+\overline{CD}

Putting the values of \overline{BD}, \overline{BC} and \overline{CD}

5x=4x+ 4

⇒5x-4x= 4

⇒x=4

So we get the value of x.

To get the value of \overline{BD} , we need to put the value of x in the value of \overline{BD}.

Therefore,

\overline{BD} = 5×4

      =20

Therefore the required value of \overline{BD} is 20 units.

3 0
3 years ago
Simplify 6/10 + 8.75?
PilotLPTM [1.2K]
First do 6 divided by 10

then add 8.75 to that 
6 0
4 years ago
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