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ikadub [295]
1 year ago
6

I need help solving this problem 8(4 -6n)= -8( -1+7n) and I want to know of I got it right

Mathematics
1 answer:
Brut [27]1 year ago
8 0

Answer:

-3

Step-by-step explanation:

The answer is - 3. Basically like solving for x. But I explained it in detail in the picture. Hope it helps

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Una pequeña empresa dedicada a la fabricación de muebles lanzará al mercado un nuevo modelo de escritorio para escolares a un pr
Pie

Answer:

Se debe fabricar y vender 553 escritorios para lograr una utilidad de S/ 25000.

Step-by-step explanation:

La utilidad por cada escritorio se obtiene al sustraer los costes fijos y variables del precio, es decir:

u = S/ \,125 -S/\,4,75 - S/\,75

u = S/\,45.25

El número de escritorios a vender para obtener S/\,25000 se calcula mediante la siguiente regla de tres simple:

x = \frac{S/\,25000}{S/\,45,25} \times 1\,esc

x = 552.486

Puesto que la cantidad a vender es una variable entera, se debe redondear al entero más cercano. En consecuencia, se debe fabricar y vender 553 escritorios para lograr una utilidad de S/ 25000.

7 0
4 years ago
Find 16-19. <br> find mQT<br> Find m find mST<br> find mRQ
lana66690 [7]

Answer:

16. 142 deg

17. 23 deg

18. 134 deg

19. 38 deg

Step-by-step explanation:

16.

m(arc)QT = 2m<QST = 2 * 71 = 142

17.

m<STR = (1/2)m(arc)RS = (1/2)46 = 23

18.

RT is a diameter since it includes the center of the circle, point X.

m(arc)RST = 180

m(arc)RS + m(arc)ST = m(arc)RST

46 + m(arc)ST = 180

m(arc)ST = 134

19.

RT is a diameter since it includes the center of the circle, point X.

m(arc)RQT = 180

m(arc)RQ + m(arc)QT = m(arc)RQT

m(arc)RQ + 142 = 180

m(arc)RQ = 38

5 0
3 years ago
Read 2 more answers
HELP MEEEE PLEASE!!!
Zielflug [23.3K]

Answer:

the last option

Step-by-step explanation:

test with point (1,6):

x=1 and y=6

4x + 5y - 34 = 0

4(1) + 5(6) - 34 = 0

0 = 0

test with point (6,2)

x=6 and y=2

4x + 5y - 34 = 0

4(6) + 5(2) - 34 = 0

0 = 0

6 0
4 years ago
A university cafeteria line in the student center is a
nirvana33 [79]

Answer:

Lamda= 4 students/min, µ= 5 students/min  

P= Lamda/µ= 4/5= 0.8

a.) Probability that system is empty= P0= 1-P= 1-0.8= 0.2

b.) Probability of more than 2 students in the system= ∑(n=3 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2)= (.2)*(5-  - .2 - (.8)*.2 – (.2)*.8^2))= 0.848

Probability of more than 3 students in the system= ∑(n=4 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2 – (1-P)*P^3)= 0.768

c.) W(q)= Waiting time in Queue= lamda/µ(µ- lamda)= 4/5(1)= 0.8 minutes

d.) L(q)= lamda*W(q)= 4*.8= 3.2 students

e.) L(System)= lamda/(µ-lamda)= 4 students.

f.) If another server with same efficiency as the 1st one is added, then µ= 6 sec/student= 10 students/min.

P= 4/10= 0.4

Probability that system is empty= P0= 1-.4= 0.6

W(q)= 4/10(10-4)= 0.0667 minutes

L(q)= Lamda*W(q)= 4*.0667=0.2668

L(system)= Lamda/(µ-lamda)= 4/6= .667

Step-by-step explanation:

6 0
4 years ago
HELP ME PLEASE IT'S URGENT
Oduvanchick [21]
The answer would be d
Explanation: the second numbers are both the same, therefore they would be in the same line, and 7-1=6, leaving 6 units between them, I hope this helps :)
6 0
3 years ago
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