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S_A_V [24]
3 years ago
7

HELP MEEEE PLEASE!!!

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

the last option

Step-by-step explanation:

test with point (1,6):

x=1 and y=6

4x + 5y - 34 = 0

4(1) + 5(6) - 34 = 0

0 = 0

test with point (6,2)

x=6 and y=2

4x + 5y - 34 = 0

4(6) + 5(2) - 34 = 0

0 = 0

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A rectangle with sides 12 cm and 14 cm has the same diagonal as a square.
umka2103 [35]

Answer:

a=\sqrt{170}

Step-by-step explanation:

<u>Diagonal of a Square</u>

Given a square of length side a, the length of the diagonal is

D=\sqrt{2}a

The diagonal of a rectangle of sides x and y is

D=\sqrt{x^2+y^2}

The sides have lengths 12 cm and 14 cm, the diagonal is

D=\sqrt{12^2+14^2}

D=\sqrt{340}

Since this value is the same of the diagonal of certain square, we can say

\sqrt{2}a=\sqrt{340}

Dividing by \sqrt{2}

\boxed{a=\sqrt{170}}

6 0
3 years ago
Can someone help me with this please.
olga2289 [7]
C to your question for this
4 0
4 years ago
A baker is calculating the charge for two types of cookies.
eimsori [14]

Answer:

B)T=2.50c+1.50L that my answer

5 0
3 years ago
A rectangular storage container with an open top is to have a volume of 10 cubic meters. The length of its base is twice the wid
drek231 [11]

Answer:163.54$

Step-by-step explanation:

Given data

Volume of Storage(V)={10m^3}

Length=2breadth

Let Length be L,Breadth be & height be H

therefore

10=LBH

Now substitutes the values

10=2{B^2}H

5={B^2}H

Now cost for base is {C_1}=2{B^2}\times10

Cost for side walls is{C_2}={2LH}\times6+2BH}\times6

Now total cost(C)={C_1}+{C_2}

C=20{B^2}H+{2LH}\times6+2BH}\times6

C=20{B^2}H+24BH+12BH

C=20{B^2}+36B\times\frac{5}{B^{2}}

Now Differentiating With respect to Breadth to get minimum cost

\frac{\mathrm{d} C}{\mathrm{d} B}=0

we\ get\ B=\sqrt[3]{4.5}=1.65m

L=3.30m

H=1.836m

and mimimum cost C

{C=163.54\$}

7 0
4 years ago
WILL GIVE BRAINLIEST
masya89 [10]

Answer:

y = 3x + 4

y=mx+c, m represents the slope while c the y-intercept. (never forget that)

4 0
3 years ago
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