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4 years ago

What is 2(log38+logzz)-log3(34 – 72) written as a single logarithm?

Mathematics

1 answer:

Alona [7]4 years ago

6 0

Answer: log3 2z

Step-by-step explanation:

Just did it on Edge

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How do I get this equation to equal 130 by putting parentheses in it...310-20÷2×5+13

elena-14-01-66 [18.8K]

The correct is 283 maybe

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4 years ago

Solve:<br> (a+b+c) (a+b-c)

Katen [24]

Answer:

Step-by-step explanation:

Solve:

(a+b+c) (a+b-c)=

(a²+ab-ac+ab+b²-bc+ac+bc-c²)=

a²+ab-ac+ab+b²-bc+ac+bc-c²=

a²+2ab+0ac+b²+0bc-c²=

a²+2ab+b²-c²

7 0

3 years ago

Read 2 more answers

5m - 8 > 12<br> solve each problem showing your steps

Mashutka [201]

Answer:

m > 4

Step-by-step explanation:

5m - 8 > 12

Add 8 to each side

5m - 8+8 > 12+8

5m > 20

Divide by 5

5m/5 > 20/5

m > 4

3 0

3 years ago

Picture linked below

finlep [7]

Answer:

60.32 cm²

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Lisa is 53 3 4 inches tall. Joey is 1 1 2 inches shorter than Lisa and Jane is 1 1 5 inches shorter than Joey. How tall is Jane?

tester [92]

Answer: Jane's height = $51\dfrac{1}{20}\text{ inches}$

Step-by-step explanation:

Given: Lisa's height = $53\dfrac34\text{ inches}=\dfrac{4\times53+3}{4}\text{ inches}$

$=\dfrac{215}{4}\text{ inches}$

Joey's height = $\dfrac{215}4-1\dfrac12$ inches

$=\dfrac{215}4-\dfrac32\\\\=\dfrac{215-6}{4}\\\\=\dfrac{209}{4}\text{ inches}$

Jane's height = $\dfrac{209}{4}-1\dfrac15$ inches

$=\dfrac{209}{4}-\dfrac{6}{5}\\\\=\dfrac{209\times5-6\times4}{20}\\\\=\dfrac{1045-24}{20}\\\\=\dfrac{1021}{20}\\\\=51\dfrac{1}{20}\text{ inches}$

Hence, Jane's height = $51\dfrac{1}{20}\text{ inches}$

3 0

3 years ago