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Rzqust [24]
1 year ago
6

MATHEMATICS Evaluate (0.110 two)³ expressing your answer in base ten.

Mathematics
1 answer:
zysi [14]1 year ago
4 0

Evaluating (0.110 two)³ in base ten is  (343/512) ten

The question has to do with number base

<h3>What is number base?</h3>

A number base is a system of numbering used to represent numbers.

<h3>How to evaluate  (0.110 two)³ in base ten.</h3>

Since we have  (0.110 two)³,we desire to convert  0.110 two to base ten.

So, converting 0.110 two to base ten, following the procedure, we have that

0.110 two = 0 × 2⁰ + 1 × 2⁻¹ + 1 × 2⁻² + 1 × 2⁻³

= 0 × 2⁰ + 1 × 1/2¹ + 1 × 1/2² + 1 × 1/2³

= 0 × 1 + 1 × 1/2 + 1 × 1/4 + 1 × 1/8

= 0 + 1/2 +1/4 + 1/8

= (4 + 2 + 1)/8

= 7/8

So, thus 0.110 two = (7/8) ten

Thus we see that (0.110 two)³ = (7/8)³ ten

= (343/512) ten

So, expressing (0.110 two)³ in base ten is  (343/512) ten

Learn more about number base here:

brainly.com/question/27072175

#SPJ1

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D. 5x+5y=10

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1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}

Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

So,α=\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}

β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

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