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Kay [80]
3 years ago
7

What was the change of state at boiling point? How did the molecules react?

Chemistry
1 answer:
Volgvan3 years ago
7 0

Explanation:

At the boiling point the phase change from liquid to gas,, molecules react by becoming further apart from each other due to increase of their kinetic energy as supplied by heat to change their state to gas(boiling point)

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fomenos
I believe the answer is E. They behave ideally at high temperature and low pressure.
Hope this helps.
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3 years ago
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What is the compound KNC called?
rodikova [14]
The answer is <span>Potassium cyanide</span>
5 0
4 years ago
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A gas with a volume of 4.0L at a pressure of 205kPa is allowed to expand to a volume of 12.0L. What is the pressure in the conta
mr Goodwill [35]

Answer:

68.3 kilo Pascal is the pressure in the container.

Explanation:

To calculate the new pressure , we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=205kPa\\V_1=4.0 L\\P_2=?\\V_2=12.0 L

Putting values in above equation, we get:

P_2=\frac{P_1V_1}{V_2}

=\frac{205 kPa\times 4.0 L}{12.0 L}=68.3 kPa

68.3 kilo Pascal is the pressure in the container.

5 0
3 years ago
The change in frequency of a wave acceleration​
nikdorinn [45]

Answer:

it decreases the amplitude of the wave as it propagates

Explanation:

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=H_2PO_4%5E-%28aq%29%20%5Crightarrow%20H%5E%2B%28aq%29%20%2B%20HPO_4%5E%7B2-%7D%28aq%29" id="Te
klasskru [66]

Answer:

The pH of the buffer solution = 8.05

Explanation:

Using the Henderson - Hasselbalch equation;

pH = pKa₂ + log ( [HPO₄²-]/[H₂PO4⁻]

where pKa₂ = -log (Ka₂) = -log ( 6.1 * 10⁻⁸) = 7.21

Concentration of OH⁻ added = 0.069 M (i.e. 0.069 mol/L)

[H₂PO4⁻] after addition of OH⁻ = 0.165 - 0.069 = 0.096 M

[HPO₄²-] after addition of OH⁻ = 0.594 + 0.069 = 0.663 M

Therefore,

pH = 7.21 + log (0.663 / 0.096)

pH = 7.21 + 0.84

pH = 8.05

4 0
3 years ago
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