Answer:
58.29
Step-by-step explanation:
1/2 × (7+10.4) × 6.7
= 58.29
Answer:
Second class have higher marks and greater spread.
Step-by-step explanation:
First box plot represents class first. From the first box plot, we get
Second box plot represents class second. From the second box plot, we get
First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.
Second class has greater range and greater inter quartile range. It means data of second class has greater spread.
Therefore, second class have higher marks and greater spread.
Answer:
Last Option; 84 cu. mm
Step-by-step explanation:
We know that;
Volume = 1/3(Bh)
And that this is figure has a square base, therefore B that represents the area of the base will be: 6 * 6 = 36
And height = 7mm
Therefore we can say;
Volume = (1/3)*(6 x 6)*(7)
Volume = (1/3)*(36)*(7)
Volume = (12)*(7)
<u>Volume = 84</u>
Hope this helps!
Answer:
-14.4<or=z
Step-by-step explanation:
-8-6.4or = z+6.4-6.4
-14.4_<z
Answer:
P(a junior or a senior)=1
Step-by-step explanation:
The formula of the probability is given by:
Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.
In this case, N is the total number of the students of statistics class.
N=18+10=28
The probability of the union of two mutually exclusive events is given by:
Therefore:
P(a junior or a senior) =P(a junior)+P(a senior)
Because a student is a junior or a senior, not both.
n(a junior)=18
n(a senior)=10
P(a junior)=18/28
P(a senior) = 10/28
P(a junior or a senior) = 18/28 + 10/28
Solving the sum of the fractions:
P(a junior or a senior) = 28/28 = 1