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Kaylis [27]
4 years ago
7

Alguien me podría ayudar

Mathematics
1 answer:
BaLLatris [955]4 years ago
7 0

Answer:

yessir

Step-by-step explanation:

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You are given a number line with a left endpoint R, a point in between the two endpoints (not a midpoint though) of S, and a rig
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You just add the lengths of RS and ST together. In your case RT= 24
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Expand and simplify 5(3x+2)-2(4x-1)
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Answer:

15x+10-8x+2

7x+12

Step-by-step explanation:

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3 years ago
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Find the distance travelled by Rubina if she takes 4 rounds of rectangular park whose length and breadth is 45m and 30m
ANTONII [103]
  • Length (l) = 45 m
  • Breadth (b) = 30 m
  • We know, perimeter of a rectangle = 2(length + breadth)
  • Therefore, perimeter of the rectangle
  • = 2(I + b)
  • = 2(45 + 30) m
  • = 2 × 75 m
  • = 150 m
  • So, the distance travelled by Rubina
  • = 4 × 150 m
  • = 600 m

<u>Answer:</u>

<em><u>The </u></em><em><u>distance </u></em><em><u>travelled</u></em><em><u> </u></em><em><u>by </u></em><em><u>Rubina </u></em><em><u>is </u></em><em><u>6</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>m.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0
3 years ago
Peter buried a treasure chest on a remote island and is.making a map so he can find it later. One of the key landmarks in the ar
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Where’s the rest of the question?
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3 years ago
An airplane climbs 100 feet during the first second after takeoff. In each succeeding second it climbs 100 feet more than it cli
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Answer:

15 seconds.

Step-by-step explanation:

∵ The distance covered by plane in first second = 100 ft,

Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,

So, distance covered in second second = 200,

In third second = 300,

In fourth second = 400,

............, so on....

Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds

=\frac{n}{2}(2\times 100 + (n-1)100)  ( Sum of AP )

=\frac{n}{2}(200+100n-100)

=\frac{n}{2}(100+100n)

=50n+50n^2

Suppose the distance covered in n seconds is 12,000 feet,

\implies 50n+50n^2=12000

n+n^2=240

n^2+n-240=0

n^2+16n-15n-240=0

n(n+16)-15(n+16)=0

(n-15)(n+16)=0

\implies n=15\text{ or }n=-16

∵ n can not be negative,

Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.

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3 years ago
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