Write the equation of a circle in standard form with a diameter whose endpoints are

If there are 22 successes in a sample with a size of 40, what is the sample

patriot [66]

Answer:

A

Step-by-step explanation:

22 successes out of a group of 40 means 22/40 were good. Now, simplify 22/40. Both can be divided by 2.

22/2 = 11

40/2 = 20

Now you have 11/20. Put this in decimal form and you have 0.55

3 0

2 years ago

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2) Prove that these two lines are parallel:

borishaifa [10]

Answer:

if the two lines have the same slope that means they are parallel

3 0

3 years ago

Which expression is equivalent to −19y+13 ?

Vikki [24]

The first thing you should do in this case is to write the expression correctly:
- (1/9) y + (1/3)
Now, we take out common factor (1/9) obtaining:
1/9 (-y + 3)
Let's check:
1/9 (-y + 3)
-1/9y + 3/9
-1/9y + 1/3
OK
Answer:
An expression equivalent is:
1/9 (-y + 3)

4 0

2 years ago

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On the grid draw the graph of y = 3x + 2 for values of x + 2 for values of x from -2 to 2

sladkih [1.3K]

Answer:

The required graph is shown below.

Step-by-step explanation:

Consider the provided equation $y=3x+2$

We need to draw the graph of the equation.

Put x=0 in the above equation.

$y=3(0)+2$

$y=2$

The coordinate is (0,2).

Put y=0 in the given equation.

$0=3x+2$

$-2=3x$

$x=\frac{-2}{3}$

The coordinate is ( $\frac{-2}{3}$ ,0).

Now draw the graph by using the above coordinates.

The required graph is shown below.

6 0

2 years ago

The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili

Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .