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3 years ago

Write the rule for the table below help me pleaseeeeeeeeee

Mathematics

1 answer:

Anna71 [15]3 years ago

7 0

-5 like minus 5 no mater the negetive for y
Hope this helped ")

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Factor this expression completely, then place the factors in the proper location on the grid. a^3y + 1

ivolga24 [154]

Answer:

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

Step-by-step explanation:

We are to factorize the expression $a^{3y} + 1$ completely. To do this, we will apply the expression below;

The expression can be rewritten as $a^{3y} + 1^{3}$

To factorize the expression, we need to first factorize $(a^{y}+1 )^{3}$ first

$(a^{y}+1 )^{3} =(a^{y}+1 )(a^{y}+1 )^{2}\\= (a^{y}+1 )((a^y)^{2} } + 2a^{y} +1)\\= (a^y)^{3} +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y+1\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +3(a^y)^{2}+3a^y\\$

The we will make $a^{3y} + 1^{3}$ the subject of the formula as shown;

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\(a^y)^{3} + 1^{3} = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

This last result gives the expansion of the expression

7 0

3 years ago

1. m- 7 5.5

Andreas93 [3]

The first answer is 2.5 and I don’t know the last two sorry

5 0

2 years ago

Simplify

bazaltina [42]

The answer I got is 17x-70/5

4 0

2 years ago

As a salesperson, you are paid $50 per week plus $3 per sale. This week you want your pay to be at least $110. What is the minim

alexgriva [62]

110 (goal) - 50 (base pay) = 60 (pay from sales only)

60 (total pay from sales) / 3 (cost per individual sale) = 20 (qty of sales)

7 0

2 years ago

Read 2 more answers

What does ƒ(x) = 3x − 1, for ƒ(-2) mean?

zzz [600]

Answer:

C. It means to input a -2 into the function to find the output.

Step-by-step explanation:

f(x) means to the function of x. The question is asking you to input -2 for x and find the answer.

6 0

2 years ago