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1 year ago

a highway is to be built between two towns, one of which lies 48.6 km south and 60.3 km west of the othe

Mathematics

1 answer:

Katena32 [7]1 year ago

8 0

Answer:

whats the rest of the question or what's the available answers

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How many more pairs of parallel sides does a regular octagon have than a

iVinArrow [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

WORTH 25 POINTS PLEASE HELP!!!

GalinKa [24]

Just subtract the smaller volume from the larger:

10 × 10 ×15 - 7 × 9 × 12

First you would multiply 10 × 10 × 15 = 1500 and then multiply 7 × 9 × 12 = 756.

After you would subtract 1500 - 756 which would give you 744

I hope that helped!

7 0

4 years ago

Read 2 more answers

The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2

Darina [25.2K]

Answer:

a) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 0$ are $x_{1}\approx -0.25$ and $x_{2} \approx 1.25$ .

b) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 2$ are $x_{1}\approx -0.5$ and $x_{2} \approx 1.5$

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial $y = 4\cdot x^{2}-4\cdot x -1$ , where $x$ is related to the horizontal axis of the Cartesian plane, whereas $y$ is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:

a) $4\cdot x^{2}-4\cdot x -1 = 0$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.25$ , $x_{2} \approx 1.25$

b) $4\cdot x^{2}-4\cdot x -1 = 2$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.5$ , $x_{2} \approx 1.5$

5 0

3 years ago

The table shows a student's proof of the quotient rule for logarithms.

nikklg [1K]

Answer:

The error is at step (3) .

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

Step-by-step explanation:

The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by assuming the property does hold before proving it. So, the proof is fallacious.

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

5 0

3 years ago

Kylie explained that (negative 4 x + 9) squared will result in a difference of squares because (negative 4 x + 9) squared = (neg

Eva8 [605]

Given:

The given expression is:

$(-4x+9)^2$