7/10 in its simplest form is 0.7
Solve for x.
c=8x+60
Flip the equation.
8x+60=c
Add -60 to both sides.
8x+60+−60=c+−60
8x=c−60
Divide both sides by 8.
8x/8=c−60/8
x=1/8c + −15/2
Answer:
If the proportions of all people who carry the trait are the same for both populations, the probability of observing a sample difference of at least 0.22 is 0.03
Step-by-step explanation:
Given the hypothesis :
H0 : pW = pX
Ha : pW > pX
W - X = 0.22
Pvalue = 0.03
Since the Pvalue gives the probability of obtaining a value or result figure which is atleast as extreme as the observed value. The observed value here is 0.22 resulting from the difference in W and X (W - X).
This can thus be interpreted to mean ; going by the Null (difference between W and X) ; the probability of obtaining a value of atleast 0.22 as difference is 0.03
