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Semmy [17]
1 year ago
11

Explain why the graph of the equation g(x)=-(x+1)^2-3 would be a parabola opening downward

Mathematics
1 answer:
Mrac [35]1 year ago
7 0

We know that the parabola opens downwards because it has a negative leading coefficient.

<h3></h3><h3>Why the parabola opens downwards?</h3>

For any polynomial, the leading coefficient is the coefficient in the term where is the large exponent of the polynomial.

The sign of that coefficient will determine the end behavior of the graph of the polynomial.

For the case of the parabola, a positive leading coefficient means that the parabola opens upwards, while a negative leading coefficient will mean that the parabola opens downwards.

Now, if you look at our parabola:

g(x) = -(x + 1)^2 - 3

You can see that there is a negative sign, thus when we expand the parenthesis, we will end up with a negative leading coefficient:

g(x) = -x^2 - 2x + 1 - 3 = -x^2 -2x - 2

So we know that the parabola opens downwards.

If you want to learn more about parabolas:

brainly.com/question/4061870

#SPJ1

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A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
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Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

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