Hey there,
First, find the square root of the given equation.
Keep in mind that this is solved for k = 0 and 1.
Second, simplify.
![=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})](https://tex.z-dn.net/?f=%3D9%5Ctext%7Bcos%7D%28%5Cfrac%7B2%5Cpi%7D%7B9%7D%29%2Bi%5Ctext%7Bsin%7D%28%5Cfrac%7B2%5Cpi%7D%7B9%7D%29~%5Ctext%7Bor%7D~9%5Ctext%7Bcos%7D%28%5Cfrac%7B11%5Cpi%7D%7B9%7D%29%2Bi%5Ctext%7Bsin%7D%28%5Cfrac%7B11%5Cpi%7D%7B9%7D%29)
Best of Luck!
Answer:
6:9 ÷3
2:3
Step-by-step explanation:
1st write the ratio then simplify it with dividing with the Highest common factor on both sides
Answer:
letter a
Step-by-step explanation:
0.3 + 0.4= 0.8
X = cos(pi/6) = √3/2
y = sin(pi/6) = 1/2
So at point (√3/2, 1/2)
Answer:
a = 82
b = 130
c = 118
Step-by-step explanation:
A quadrilateral is inscribed in a circle. So, it is a cyclic quadrilateral.
Opposite angles of a cyclic quadrilateral are supplementary.
Therefore,
a° + 98° = 180°
a° = 180° - 98°
a° = 82°
a = 82
By inscribed angle theorem:
a° = 1/2(b° + 34°)
82° * 2 = b° + 34°
164° - 34° = b°
b° = 130°
b = 130
Again by inscribed angle theorem:
76° = 1/2(c° + 34°)
76° *2 = c° + 34°
152° - 34° = c°
c° = 118°
c = 118