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Katena32 [7]
3 years ago
15

If you currently swim 5 laps a day, 3 days a week, and you want to add on 2 laps per day that you swim. Write an equation in fun

ction form that gives the total number of laps as a function of the number of times you have been swimming since you started adding laps. Then, find the total number of laps you swim in 8 weeks if you swim 3 times a week.
Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0
Two more laps per swimming day make 7 laps. If y is total laps and the number of swimming days, y=f(x)=7x.
The value of x=8×3=24 swimming days. Therefore y=7×24=168 laps.
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15PTS!!!! HELPPPP!!! Determine the length of fencing around an 80 m by 170 m rectangular playing field if fence is to be 25 m ou
marshall27 [118]
Perimeter=2L+2W, in this case L=80+2(25) and W=170+2(25) so

P=2(L+W)=2(80+50+170+50)

P=2(350)=700m
5 0
3 years ago
A pizza shop has recently sold 15 pizzas. 5 of those pizzas were pepperoni. Answering with a fraction, what is the experimental
rewona [7]

Answer: 1/3

Step-by-step explanation:

if you make a fraction 5/15 pizzas and simplify it is is equal to 1/3.

7 0
2 years ago
Which statements correctly use the properties of exponents to simplify? Check all that apply.
defon
The first one, second, and third
9 0
3 years ago
Read 2 more answers
Given that LM and LN are tangent to the circle and that the measure of angle MLN = 75.86, find the measure of arc MN.
siniylev [52]

we know that

The measure of the external angle is the semidifference of the arcs that it covers

so

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

Let

x------> minor arc MN

major arc MN=360-x

substitute in the formula above

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x

x=104.14°

therefore

the answer is

the measure of arc MN (minor arc) is 104.14°

7 0
3 years ago
What is the period of y=3cot(4x−3π)
Stells [14]
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


Hope this Helps! Have A Wonderful Day! :)</span>
4 0
3 years ago
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