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2 years ago

Please help for brainiest !!!!

Mathematics

1 answer:

hjlf2 years ago

3 0

Answer:

E) Line 5

Step-by-step explanation:

Line 5 contains the first incorrect mathematical process

Process

x−5(x+1)>3x+2

−4x−5>3x+2

−7x−5>2

−7x>7

x<−1

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The total weight of 30 bags of flour and 4 bags of sugar is 42.6 kg. If each bag of sugar weighs 0.75 kg, what is the weight of

tigry1 [53]

30 bags of flour + 4 bags of sugar = 42.6 kg
each bag of sugar weighs 0.75 kg
each bag of flour weighs x kg = ?

If you would like to know what is the weight of each bag of flour, you can calculate this using the following steps:

30 * x + 4 * 0.75 kg = 42.6 kg
30 * x + 3 kg = 42.6 kg
30 * x = 42.6 kg - 3 kg
30 * x = 39.6 kg /30
x = 39.6 kg / 30
x = 1.32 kg

Result: Each bag of flour weighs 1.32 kg.

4 0

3 years ago

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Find the equation (in terms of x ) of the line through the points (-4,-4) and (2,4)

Greeley [361]

Answer:

$y=\frac{4}{3}x+\frac{4}{3}$

Step-by-step explanation:

Let $(x_1,y_1)\rightarrow(-4,-4)$ and $(x_2,y_2)\rightarow(2,4)$ :

Determine slope

$m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{4-(-4)}{2-(-4)}\\ \\m=\frac{4+4}{2+4}\\ \\m=\frac{8}{6}\\ \\m=\frac{4}{3}$

Use either coordinate point to find "b", the y-intercept

$y=mx+b\\\\4=\frac{4}{3}(2)+b\\ \\4=\frac{8}{3}+b\\ \\\frac{4}{3}=b$

Final Equation

$y=\frac{4}{3}x+\frac{4}{3}$

5 0

3 years ago

Sheila is now 15 years older than her younger brother sanjay.ten years from now,sheila will be twice as old as sanjay.find the p

miv72 [106K]

Sheila is 20

Sanjay is 5

6 0

4 years ago

Can someone help with this question

poizon [28]

(5x+2)(4x+4)
20x² + 20x + 8x + 8
20x² + 28x + 8

8 0

3 years ago

The savings account offering which of these APRs and compounding periods offers the best APY?

zzz [600]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\
$

$\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\
$

$\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1$

7 0

3 years ago

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