This might be your answer
(-5/2, 5/2)
Step-by-step explanation:
dP/dt = -0.4P
Separate the variables and integrate.
dP/P = -0.4 dt
ln|P| = -0.4t + C
P = Ce^(-0.4t)
Use initial condition to find C.
2 = C^(0)
C = 2
P = 2e^(-0.4t)
dQ/dt = -1
Integrate.
Q = -t + C
Use initial condition to find C.
3 = 0 + C
C = 3
Q = -t + 3
Set the two equal.
2e(-0.4t) = -t + 3
Use a calculator to find t.
t = 2.156
The populations have the same size after 2.156 hours.
<span>The diagonals of a parallelogram bisect each other.
So we just equate the two equations BE and DE
2x^2 - x = x^2 + 6
2x^2 - x - x^2 - 6 = 0
x^2 - x - 6 = 0
This is quadratic eqn. So we obtain.
(x - 3) ( x + 2) = 0
Setting each to 0 and solving for x, we have that x = 3 and x = -2
So we have two possible values for BD.
But Since BE = DE then we can simply double each
If x = 3 BD = 2 (2(3)^2 - 3) = 2 ( 18 - 3) = 30 units
If x = - 2 BD = 2((-2)^2 -3 ) = 2 (8 - 3) = 10 units</span>
Step-by-step explanation:
= 10x - 5 + 3x - 2
= (10 + 3)x + (-5 - 2)
= 13x - 7
