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Mariana [72]
4 years ago
6

Mateo has received a Word document from a customer that contains private information and is secured with a password. However, wh

en Mateo tries to open the
document in his browser, he gets an error message. How might he fix this problem?
a Use a secure website that starts with HTTPS
b. Open the document in the Word app installed on his computer
c Save the document in the cloud
d Ensure there's a lock icon in the browser
Computers and Technology
2 answers:
natali 33 [55]4 years ago
6 0

Answer:

open it in a different app

Explanation:

Lana71 [14]4 years ago
5 0
I think B is the answer
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3. The wildlife department has been feeding a special food to rainbow trout finger lings in a pond. A sample of the weight of 40
andrey2020 [161]

Answer:

1)  402.7 grams. This estimate is called the sample mean.

2)  (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

Explanation:

sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams

1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.

2) c = 99% = 0.99

α = 1 - 0.99 = 0.01

\frac{\alpha }{2} =\frac{0.01}{2} =0.005.

The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).

z_\frac{\alpha }{2} =2.58.

The margin of error (e) = z_\frac{\alpha }{2}*\frac{\sigma}{\sqrt{n} }  =2.58*\frac{8.8}{\sqrt{40} } =3.59

The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

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