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timurjin [86]
3 years ago
11

What are factors that limit a technological design

Computers and Technology
2 answers:
Oksana_A [137]3 years ago
7 0
The factors that limit a technological design can be physical and social. The physical limitations are constraints due to nature itself. They  include natural laws and properties of materials.
Social limitations on the other hand <span>are limitations that arise as a result of the society we are living in and include the ease of use, safety, attractiveness, and <span>cost.</span></span>
mote1985 [20]3 years ago
7 0
Some factors that can limit a technological design are, say the type of materials used to build it and their availability, and the skill of the artisans that make the ensuing product. For example, once I had a bridle made for carrying a piezometer (an instrument for measuring water pressure in drill holes) down a hole with a shallow dip. One limit was that somehow the bridle must utilize gravity to pull the piezometer down the hole to the desired location. Steel pipe was used to give weight to the bridle and the piezometer was taped to this. But the vertical component of the weight was too low due to the shallow hole angle so roller bearings had to be inserted in the pipe to allow it to roll down inside the steel drill rods to the desired location, thus overcoming friction which was also a limiting factor. Thanks to the skill of the machinist who made it, it was very successful and worked very well.
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Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and s
S_A_V [24]

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

int main() {

//  variable  

int num;

cout<<"Enter the number between 20 and 98: ";

// read number

cin >> num;

while(num<20||num>98)

{

   cout<<"Wrong input!!enter number between 20-98 only:";

   cin>>num;

}

cout<<"The output is: ";

while(num % 10 != num /10)

{

// print numbers.  

cout<<num<<" ";

// update num.

num--;

}

// display the number.

cout<<num<<endl;;

return 0;

}

Explanation:

Read a number from user and assign it to variable "num".Check if entered number  is in between 20-98 or not.If input number is less than 20 or greater than 98 then  ask again to enter a number between 20-98 until user enter a valid input.Then print  the countdown from input number till both the digit of number are same.

Output:

Enter the number between 20 and 98: 99                                                                                    

Wrong input!!enter number between 20-98 only:12                                                                            

Wrong input!!enter number between 20-98 only:93                                                                            

The output is: 93 92 91 90 89 88

Enter the number between 20 and 98: 77                                                                                    

The output is: 77

7 0
3 years ago
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