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Zarrin [17]
1 year ago
5

Alina had 3/5 much money as edna. edna had $32 more than alina. how muuch money would alina have if her mother gave her 1/6 more

of what she had at first?
Mathematics
1 answer:
olga_2 [115]1 year ago
4 0

Alina has $22.4 if her mother gave her 1/6 more of what she had at first.

<h3>What is a fraction?</h3>
  • A fraction is a portion of a whole or, more broadly, any number of equal parts.
  • In everyday English, a fraction describes the number of parts of a specific size, such as one-half, eight-fifths, or three-quarters.

To find how much money would Alina has if her mother gave her 1/6 more of what she had at first:

Alina has 3/5 much money as Edna.

Edna has $32.

Alina's mother gave her more 1/6 or 3/5.

So, first, we will find 1/6 of 3/5.

  • 3/5 × 1/6 = 3/30

Now, add 3/30 to 3/5.

  • 3/5 + 3/30 = 21/30.

Hence, Alina has 21/30 as much money as Edna.

Then,

  • $32 × 21/30 = $22.4

Therefore, Alina has $22.4 if her mother gave her 1/6 more of what she had at first.

Know more about fractions here:

brainly.com/question/17220365

#SPJ4

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Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

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