1/3 chance of it being a boy the first time and 2/3 chance of it being a girl second
12 x 8 = 96
+
6 x 1.5 = 9
ANSWER: $105
This should be right and I hope it helps :)
Answer:
Option A) 0.0074
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 110
Sample mean, 
= 20
Sample size, n = 100
Alpha, α = 0.05
Population standard deviation, σ = 115.35
First, we design the null and the alternate hypothesis
We use two-tailed z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now, we calculate the p-value from the standard normal table.
P-value = 0.0074
Thus, the correct answer is
Option A) 0.0074
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
<em><u>Histograms are used to represent a frequency distribution, and bar graph show a comparison between data/variables. Histograms display quantitative data with ranges of the data grouped into bins, whereas bar graphs show categorical data.</u></em>
Step-by-step explanation:
<h3><em><u>i </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it's</u></em><em><u> helpful</u></em><em><u> for</u></em><em><u> you</u></em><em><u> ✌️</u></em></h3>
