We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
Answer:
1. .26
2. .29
3. .22
4. .23
Step-by-step explanation:
3.1 ÷ 12 = .26
2.92 ÷ 10 = .29
3.52 ÷ 16 = .22
1.85 ÷ 8 = .23
<em>good luck, i hope this helps :)</em>
Answer: the value of the account after 6 years is $101559.96
Step-by-step explanation:
If $64,000 is invested in an IRA account, then
Principal = $64,000
So P = 64,000
The rate at which $64000 was compounded is 8%
So r = 8/100 = 0.08
If it is compounded once in a year, this means that it is compounded annually (and not semi annually, quarterly or others). So
n = 1
We want to determine the value of the account after 6 years, this means
time, t = 6
Applying the compound interest formula,
A = P(1 + r/n)^nt
A = amount after n number of years
A = 64000( 1 + 0.08/1)^1×6
A = 64000(1.08)^6
A= 64000×1.58687432294
A= 101559.956668416
Approximately $101559.96 to 2 decimal places
1) 7000+300+10+3
2) 900,000+90,000+400+40+6
3) 600+80+2
4)30,000+7000+900+10+1
5)3,000,000+900,000+40,000+1,000+400+70+7
6)8000+400+70+4
7)700+70+2
8)30,000+7000+200+80+2
9)700,000+30,000+5,000+800+10+1
10)40,000+6000+400+40+9
11)5000+8000+70+2
12)5,000,000+700,000+50,000+8,000+900+40+5
13)5,000,000+900,000+90,000+8,000+800+90+0
14)300+70+7
15)300,000+20,000+3,000+200+40+8
