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Marysya12 [62]
1 year ago
12

The flight of a cannonball toward a hill is described by the parabola y=2+0.12x- 0.0004x^2

Mathematics
1 answer:
Stells [14]1 year ago
6 0

The computation shows that the placw on the hill where the cannonball land is 3.75m.

<h3>How to illustrate the information?</h3>

To find where on the hill the cannonball lands

So 0.15x = 2 + 0.12x - 0.002x²

Taking the LHS expression to the right and rearranging we have:

-0.002x² + 0.12x -.0.15x + 2 = 0.

So we have -0.002x²- 0.03x + 2 = 0  

I'll multiply through by -1 so we have

0.002x² + 0.03x -2 = 0.

This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.

The second solution y = 0.15 * 25 = 3.75

Learn more about computations on:

brainly.com/question/4658834

#SPJ4

Complete question:

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

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Step-by-step explanation:

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=======================

If you use your calculator to find 2/5 and 1/5, you can get the same answer as 3/5

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3

÷

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