Amanda's age is one-half of Sally's. Which variable expression represents Amanda's age? 2s 1 2 +s s + 2 s 2

Mathematics

2 answers:

koban [17]4 years ago

5 0

Answer:

Just did the quiz, the answer is 8/2

Step-by-step explanation:

dem82 [27]4 years ago

4 0

The answer is s^2 squared to the second power

You might be interested in

Is 25.789 bigger then 25.879

dimulka [17.4K]

It is not bigger. 25.879 is bigger by .100

6 0

3 years ago

Write an equation in point-slope form of the line that passes through the point (9,0) and has a slope of m=-3 .

aksik [14]

Answer:

$y = - 3x + 27$

Step-by-step explanation:

The standard form for the equation of the line is

$y = mx + c$

Recall that:

$y = 0 \: \: \: x = 9 \: \: \: m = - 3 \\ y = mx + c \\ 0 = - 3(9) + c \\ 0 = - 27+ c \\ 27 = c$

Therefore the equation of the line is:

$y = mx + c \\ y = - 3x + 27$

5 0

2 years ago

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago

This graph represents a linear function.

Rudik [331]

Answer:

y=2x-2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please help and show work

Bogdan [553]