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HACTEHA [7]
3 years ago
5

The Alexander family is selecting a furniture set. A furniture set has a bed, a desk and a dresser. There are 2 beds, 4 desks, a

nd 1 dresser to select from. How many different furniture sets could they select?
Mathematics
2 answers:
wolverine [178]3 years ago
8 0

Answer:

8

Step-by-step explanation:

2C1 = 2 options for a bed

4C1 = 4 options for the desk

1C1 = 1 option for the dresser

Total possible selections:

2 × 4 × 1 = 8

murzikaleks [220]3 years ago
5 0

Answer:

  • 2C1 = 2 options for a bed
  • 4C1 = 4 options for the desk
  • 1C1 = 1 option for the dresser

Total possible selections:

➡️2 × 4 × 1 = 8

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Hello? i have a question.​
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Step-by-step explanation:

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3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
2 years ago
three friends go to a book fair . alvin speends 2.60 . prabhjot spends 4 times as much as alvin . stephanie spends 3.45 less the
blsea [12.9K]

Answer:

6.95

Step-by-step explanation:

to find how much stephanie spends for first we will find how much probhjot spends and then subtract 3.45 dollars from that value alvin spends 2.60 dollars

prohbjot spends 4 times as much as alvin or

4× 2.60=10.4

so prohbjot spends 10.4 dollars

stephanie spends3.45 dollars less than prohbjot or

10.4 -3.45 =6.95

so stephanie spends <u>6.95 </u>dollars

7 0
3 years ago
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