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1 year ago

Mr. Ahmed has 31 students in his class. There are 14 boys and 17 girls.

1 answer:

7 0

Since there are 14 boys and the whole class has 31 students
We get, the ratio of the part-to-whole relationship for boys is 14/31.

And since there are 17 girls
We get, the ratio of the part-to-whole relationship for girls is 17/31.

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51^7 -51^6 by 25<br> __*25

BartSMP [9]

Answer:

Step-by-step:

51⁷-51⁶ = 51⁶(51-1) = 51⁶(50)

50 is divisible by 25, so 51⁷-51⁶ is divisible by 25.

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2 years ago

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PLEASE HELP

Alexeev081 [22]

Its may be A or C
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3 years ago

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed

Lady_Fox [76]

Answer:

for 3644 produced books the costs will be the same.

Step-by-step explanation:

x = number of books

f(x) = production method 1 costs

g(x) = production method 2 costs

f(x) = 11.75x + 57077

g(x) = 21.25x + 22459

for what number of books (x) will that be the same ?

11.75x + 57077 = 21.25x + 22459

34618 = 9.5x

x = 34618 / 9.5 = 3644

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2 years ago

Please help me on this question?

NeTakaya

Four times fifteen plus twenty in parentheses
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3 0

3 years ago

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Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).

Zina [86]

we are given

$\sqrt{30} *\sqrt{610}$

we can radical formula

$\sqrt{a} *\sqrt{b}=\sqrt{a*b}$

we get

$\sqrt{30} *\sqrt{610}=\sqrt{30*610}$

$\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}$

we can also write as

$\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}$

$\sqrt{30} *\sqrt{610}=10\sqrt{183}$ ............Answer

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3 years ago

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