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bezimeni [28]
1 year ago
6

Mr. Ahmed has 31 students in his class. There are 14 boys and 17 girls.

Mathematics
1 answer:
densk [106]1 year ago
7 0
Since there are 14 boys and the whole class has 31 students
We get, the ratio of the part-to-whole relationship for boys is 14/31.

And since there are 17 girls
We get, the ratio of the part-to-whole relationship for girls is 17/31.
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Write an exponential function to model the situation. Find each amount after the specified time. A population of 120,000 grows 1
Savatey [412]
Exponential growth function is given by f(t) = A(1 + k%)^t; where A is the initial value, k is the growth rate and t is the time period.

Therefore, the required function is
f(t) = 120,000(1 + 0.012)^t = 120,000(1.012)^t

After 15 years, the new population is 120,000(1.012)^15 = 120,000 x 1.1959 = 143,512
8 0
3 years ago
On a coordinate plane, an absolute value graph has a vertex at (1, 3). Which equation represents the function graphed on the coo
Nonamiya [84]

Answer: g(x)= |x-1| + 3

Step-by-step explanation: the |x-1| means you need to move the vertex to the right by one and the +3 means you must move the vertex up by three

5 0
3 years ago
Read 2 more answers
X
quester [9]

Answer:

y=1

x=1

2x-3y=-1

2(1)-3(1)=-1

2-3=-1

-1=-1

so,that is the equation I have used to solve this

4 0
3 years ago
How do I find the Derivative of a Function where the x is a number?
lisov135 [29]

Given a function <em>g(x)</em>, its derivative, if it exists, is equal to the limit

g'(x) = \displaystyle\lim_{h\to0}\frac{g(x+h)-g(x)}h

The limit is some expression that is itself a function of <em>x</em>. Then the derivative of <em>g(x)</em> at <em>x</em> = 1 is obtained by just plugging <em>x</em> = 1. In other words, find <em>g'(x)</em> - and this can be done with or without taking a limit - then evaluate <em>g'</em> (1).

Alternatively, you can directly find the derivative at a point by computing the limit

g'(1) = \displaystyle\lim_{h\to0}\frac{g(1+h)-g(1)}h

But this is essentially the same as the first method, we're just replacing <em>x</em> with 1.

Yet another way is to compute the limit

g'(1) = \displaystyle\lim_{x\to1}\frac{g(x)-g(1)}{x-1}

but this is really the same limit with <em>h</em> = <em>x</em> - 1.

You do not compute <em>g</em> (1) first, because as you say, that's just a constant, so its derivative is zero. But you're not concerned with the derivative of some <em>number</em>, you care about the derivative of a function that depends on a <em>variable.</em>

8 0
3 years ago
HELP ASSAP WITH THIS QUESTION
leonid [27]
-3/5x+y=-8/5 but you have to change all the signs bc an standard formula needs to have a positive x so it would be: 3/5x-y=8/5
8 0
4 years ago
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