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Volgvan
1 year ago
9

Can anyone help me with this question please? I want to finish it ASAP!

Mathematics
1 answer:
ivolga24 [154]1 year ago
5 0

Answer:

y = 2x + 1

Step-by-step explanation:

The gradient of line A is

\frac{-6-(-2)}{0-2}=2

Parallel lines have the same gradient, so m = 2.

Substituting the coordinates of P into y = mx + c,

7=3(2)+c \implies c=1 \implies y=2x+1

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Two triangles are similar. The sides of one are three times as long as the sides of the other. What is the ratio of the areas of
Setler [38]

Answer:

1 : 9

Step-by-step explanation:

Given 2 similar figures with sides in ratio a : b , then

ratio of areas = a² : b²

Here the ratio of sides = 1 : 3 , thus

ratio of areas = 1² : 3² = 1 : 9

4 0
3 years ago
How to solve for this problem
Zanzabum
The answer is x= -79
6 0
3 years ago
Read 2 more answers
How many radians is 126
dexar [7]

Answer:

.7pi

Step-by-step explanation:

To convert from degrees to radians, multiply by pi/180

126 * pi/180

.7 pi

5 0
3 years ago
6. HELP
brilliants [131]
16/32 = P/100
Cross multiply
p(32) = 16(100)
32p = 1600
divide by 32 on both sides
p = 50 %
7 0
3 years ago
Can anyone help me find the coordinates (?,?) given that the shape is a parallelogram? (15 points)
xxTIMURxx [149]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right  )

Here x_1=m, y_1=n, x_2=h, y_2=0

              $=\left( \frac{m+h}{2}, \frac{n+0}{2}\right  )

$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right  )

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here x_1=0, y_1=0, x_2=x,  y_2=y

$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{x}{2}, \frac{y}{2}\right  )

Now equate the x-coordinate.

$ \frac{m+h}{2}=\frac{x}{2}

Multiply by 2 on both sides of the equation, we get

m + h = x

x = m + h

Now equate the y-coordinate.

$\frac{n}{2} =  \frac{y}{2}

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

5 0
3 years ago
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